0.10 1 point p(x) = x2-27 के शून्यक हैं :​

Question

0.10
1 point
p(x) = x2-27 के शून्यक हैं
:​

in progress 0
Kylie 1 month 2021-08-12T17:41:06+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-12T17:42:47+00:00

    Given : p(x) = x²-27  

    To Find :  शून्यक

    Solution:

    p(x) = x²-27  

    p(x) = 0

    => x²-27   = 0

    => x² = 27

    => x  = ± 3√3

    p(x) = x²-27    के शून्यक हैं  ± 3√3  

    Learn More:

    find the zeroes of the following quadratic polynomial and verify the …

    https://brainly.in/question/7884508

    If alpha and 1/alpha are zeroes of polynomial kx²-2x+k²+k . Find …

    https://brainly.in/question/7868632

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )