0.5: The equation of the right bisector of the line segment joining the point A(3,-4) and B(5,+6) is O x-y-9 is o Ox+y+9 is o

Question

0.5: The equation of the right bisector of the line
segment joining the point A(3,-4) and B(5,+6) is
O x-y-9 is o
Ox+y+9 is o
2x+2y-9 is 0
x+2y-7 is 0​

in progress 0
Arya 1 month 2021-08-20T10:03:41+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-20T10:04:54+00:00

    Step-by-step explanation:

    A(1,2) and B(−2,0) are given point

    ∴ midpoint p=(

    2

    1+(−2)

    ,

    2

    2+0

    )

    ∴ midpoint p=(

    2

    −1

    ,1)

    Also slope of AB=

    −2−1

    0−(2)

    =

    −3

    −2

    ∴ slope of AB=

    3

    2

    slope of line perpendicular to AB=

    3

    2

    −1

    =

    2

    −3

    ∴ equation of perpendicular bisector

    y−1=

    2

    −3

    (x+

    2

    1

    )

    ∴y−1=

    2

    −3

    (x+

    2

    1

    )

    ∴2y−2=−3(x+

    2

    1

    )

    ∴4y−4=−3(2x+1)

    ∴4y−4=−6x−3

    ∴4y+6x−4+3=0

    6x+4y−1=0

    ∴ equation of line 6x+4y−1=0

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