1.Simplify:(a+b–c)+(a–b+c)+(-a+b+c) 2.Thrice a number when increased by 5 gives 44. Find the number.​

Question

1.Simplify:(a+b–c)+(a–b+c)+(-a+b+c)

2.Thrice a number when increased by 5 gives 44. Find the number.​

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Savannah 1 month 2021-09-16T16:57:09+00:00 1 Answer 0 views 0

Answers ( )

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    2021-09-16T16:58:28+00:00

    Question 1.

    Simplify:(a+b–c)+(a–b+c)+(-a+b+c)

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     \huge \tt \: ☃ \: Solution

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    ⇒(a+b–c)+(a–b+c)+(-a+b+c)

    • First solve the brackets.

    ⇒a + b – c + a – b + c – a + b + c

    • Collect like terms

    ⇒a + a – a + b – b + b – c + c + c

    ⇒a + b + c

    Hence, simplify.

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    Question 2.

    Thrice a number when increased by 5 gives 44. Find the number.

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    Step by step explanation:

    To find:

    • The number

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     \huge \tt \: ☃ \: Solution

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    Let the number be x.

    So, According to question:

    ⇒3x + 5 = 44

    ⇒3x = 44 – 5

    ⇒3x = 39

    ⇒x = 39/3

    x = 13

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    Verification:

    ⇒3x + 5 = 44

    • Put x = 13

    ⇒3× ( 13) + 5 = 44

    ⇒39+ 5 = 44

    ⇒44 = 44

    Hence,verified

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    Thus , the number is 13.

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