11 liter is filled in a cylindrical vessal of height 35cm . find the diameter of the jar .

Question

11 liter is filled in a cylindrical vessal of height 35cm . find the diameter of the jar .

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Melody 1 month 2021-08-13T18:15:14+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-13T18:16:55+00:00

    SoluTion :

    • Height = 35 cm
    • Quantity of juice = 11 L

    Diagram :

    \setlength{\unitlength}{1 mm}\begin{picture}(5,5)\qbezier(2,3)(8,8)(14,3)\qbezier(2,3)(8,-4)(14,3)\put(2,-27){\line(0,2){30}}\put(14,-27){\line(0,2){30}}\qbezier(2,-27)(8,-35)(14,-27)\qbezier(2,-27)(8,-20)(14,-27)\put(8,-27){\line(0,2){30}}\put(9,-14){$\tt{h}$}\put(9,-29){$\tt{}$}\put(8,-27){\line(2,0){6}}\put(8,3){\line(2,0){6}}\put(15,-14){$\tt{Height\: = 35cm}$}\put(9,-34){$\tt{}$}\end{picture}

    ━━━━━━━━━━━━━━━━

    \underline{\boldsymbol{By\:using \: formula \: of  \: cylinder :}}

    \implies πr²h = 11000

    \implies 22/7 × r² × 35 = 11000

    \implies 110r² = 11000

    \implies r² = 100

    \implies r = 10

    ☆ Also, 2r = d, where d is the diameter.

    \implies 2r = d

    \implies 2 × 10 = d

    \implies d = 20

    • Diameter is 20 cm.

    ━━━━━━━━━━━━━━━━

    0
    2021-08-13T18:16:57+00:00

    AnswEr :

    It is given that the height of the cylinderical vessel is 35 cm and filled with 11 litre of juice.

    Diagram :

    \setlength{\unitlength}{1 mm}\begin{picture}(5,5)\qbezier(2,3)(8,8)(14,3)\qbezier(2,3)(8,-4)(14,3)\put(2,-27){\line(0,2){30}}\put(14,-27){\line(0,2){30}}\qbezier(2,-27)(8,-35)(14,-27)\qbezier(2,-27)(8,-20)(14,-27)\put(8,-27){\line(0,2){30}}\put(9,-14){$\tt{h}$}\put(9,-29){$\tt{}$}\put(8,-27){\line(2,0){6}}\put(8,3){\line(2,0){6}}\put(15,-14){$\tt{Height\: = 35cm}$}\put(9,-34){$\tt{}$}\end{picture}

    ⠀⠀⠀⠀⠀\rule{160}3

    \underline{\boldsymbol{Let\:us \:calculate\: the\: volume :}}

    1L = 1000cm³

    11 L = 11000cm³.

    Also,

    \underline{\boldsymbol{By\:using \: formula \: of  \: cylinder :}}

    \implies πr²h = 11000

    \implies 22/7 × r² × 35 = 11000

    \implies 110r² = 11000

    \implies r² = 100

    \implies r = 10

    ☆ As we know that 2r = d, where d is the diameter.

    \implies 2r = d

    \implies 2 × 10 = d

    \implies d = 20

    Therefore, diameter is 20 cm.

    ⠀⠀⠀⠀⠀\rule{160}3

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