12. In trapezium ABCD, AB is parallel to DC; P and Q are the mid-points of AD and BC respectively. BP produced meets CD produ

Question

12. In trapezium ABCD, AB is parallel to DC;
P and Q are the mid-points of AD and BC
respectively. BP produced meets CD
produced at point E.
Prove that :
(i) Point P bisects BE,
(ii) PQ is parallel to AB.​

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Anna 4 weeks 2021-08-17T10:40:17+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-17T10:41:25+00:00

    Answer:

    Step-by-step explanation:

    Proved that point P bisects BE  & PQ ║ AB  in Trapezium AB ║ DC  , P & Q mid points of AD & BC,   BP produced meets CdD Produced at E

    Step-by-step explanation:

    in ΔPED  & ΔPBA

    PD = PA   ( as P is mid point of DA)

    ∠EPD = ∠BPA  ( opposite angle)

    ∠PDE = ∠PAB  ( as CD ║ AB)  

    ΔPED  ≅ ΔPBA

    PE = BP

    =>  point P bisects BE

    in Δ EBC & ΔPBQ

    EB/PB = BC/BQ = 2

    => PQ ║ CE

    => PQ ║ CD

    =>  PQ ║ AB

    draw the figure by your own it is only

    0
    2021-08-17T10:42:02+00:00

    Answer:

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    Step-by-step explanation:

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