125 PO ACA…) ALMN – A POR, 9 x A (APOR ) = 16 XA (ALMN), IT OR = 20 then find MN Areas of two similar triangles are 22

Question

125
PO
ACA…)
ALMN – A POR, 9 x A (APOR ) = 16 XA (ALMN), IT OR = 20 then find MN
Areas of two similar triangles are 225 sq.em. 81 sq.em. If a side of the smaller
5.​

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Harper 1 month 2021-08-13T06:41:38+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-13T06:43:06+00:00

    THANK YOU HOPE ITS HELPFUL

    0
    2021-08-13T06:43:07+00:00

    Answer:

    hi

    hope this helps☺️

    Step-by-step explanation:

    Answer

    Given that ∆LMN and ∆PQR similar triangles.

    9 × Area ( ∆PQR) = 16 × Area(∆LMN)

    Area of ∆LMN : Area of ∆PQR = 9:16

    We know that,

    Area of two similar triangles is always Equal to square of their corresponding sides.

    Therefore,

    Area ( ∆LMN) / Area ( ∆PQR) = (MN/QR)²

    9/16 = (MN)² / (20)²

    9/16 = (MN)² / 400

    (MN)² = 9×400/16

    (MN) = ✓9×400/16

    MN = 3×20/4

    MN = 3 × 5 = 15 cm

    HOPE IT WILL HELP YOU……. 🙂

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