## 19. The total number of ways in which six ‘+’ and four ‘- signs can be arranged in a line such that no two ‘-‘ signs occur togeth

Question

19. The total number of ways in which six ‘+’ and four ‘- signs can be arranged in a line such
that no two ‘-‘ signs occur together is
(a) 7!/3
(b) 6!_7!/3(c) 35
(d) none of these

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1 month 2021-08-12T19:55:04+00:00 1 Answer 0 views 0

Among 6

+

there are 7 intervals

X+X+X+X+X+X+X

Number of ways of filling 7 gaps by 4

=

7

C

4

=35

∴ Required ways =35