2.15: If the points A(6, 1), B(8.2), C(9.4) and D(p. 3) are the vertices of a parallelogram, taken in order, find the value of p​

Question

2.15: If the points A(6, 1), B(8.2), C(9.4) and D(p. 3) are the vertices of a parallelogram, taken in order,
find the value of p​

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5 days 2021-09-14T18:13:40+00:00 1 Answer 0 views 0

To Find :

• value of p = ?

DIAGRAM :

Step-by-step explanation:

O is the mid point of AC and BD {Diagonal of parallelogram bisect each other}

1) Finding mid point of AC

x coordinate of O =

Where, and

$$\sf \dfrac{6 + 9}{2}$$

$$\sf \dfrac{15}{2}—-(1)$$

2) Finding mid point of BD

x coordinate of O =

Where, and

$$\sf \dfrac{8+p}{2}—-(2)$$

Comparing equation (1) and (2), we get :

$$\sf \dfrac{15}{2} = \dfrac{8+p}{2}$$

$$\sf 15 = 8+p$$

$$\sf p = 15 – 8$$

$$\sf p = 7$$

Therefore, value of p is 7.