2 cube root 250 + 8 cube root 16 – 3 cube root 54 + 4th root 32

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2 cube root 250 + 8 cube root 16 – 3 cube root 54 + 4th root 32

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Kylie 1 month 2021-10-27T03:37:26+00:00 1 Answer 0 views 0

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    2021-10-27T03:39:21+00:00

    2 \sqrt[3]{250}  + 8 \sqrt[3]{16}  - 3 \sqrt[3]{54}  +  \sqrt[4]{32}  \\  \\  \tt =  > 2 \sqrt[3]{2 \times  {5}^{3} }  + 8 \sqrt[3]{2 \times  {2}^{3} }  - 3 \sqrt[3]{2 \times  {3}^{3} }  +  \sqrt[4]{ 2 \times {2}^{4} }  \\ \tt  =  > 10 \sqrt[3]{2}  + 16 \sqrt[3]{2}  - 9 \sqrt[3]{2}  + 2 \sqrt[4]{2}  \\   \tt=  >  \sqrt[3]{2} (10 + 16 - 9) + 2 \sqrt[4]{2}  \\  \tt =  >  \sqrt[3]{2} (26 - 9) + 2 \sqrt[4]{2}  \\ \tt  =  >  \red{17 \sqrt[3]{2}  + 2 \sqrt[4]{2} }

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