(x-2 underroot6) (5 under root3+5 under root2) /5 under root 3-5 under root 2​

Question

(x-2 underroot6) (5 under root3+5 under root2) /5 under root 3-5 under root 2​

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Allison 5 months 2021-12-27T11:19:17+00:00 1 Answer 0 views 0

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    2021-12-27T11:20:20+00:00

    Answer:

    Step-by-sStep-by-step explanation:


    given that


    \frac{7\sqrt{3}}{\sqrt{10}+\sqrt{3}}-\frac{2\sqrt{5}}{\sqrt{6}+\sqrt{5}}-\frac{3\sqrt{2}}{\sqrt{15}+3\sqrt{2}}\\\\=\frac{7\sqrt{3}}{\sqrt{10}+\sqrt{3}}*\frac{\sqrt{10}-\sqrt{3}}{\sqrt{10}-\sqrt{3}} -\frac{2\sqrt{5}}{\sqrt{6}+\sqrt{5}}*\frac{\sqrt{6}-\sqrt{5}}{\sqrt{6}-\sqrt{5}}-\frac{3\sqrt{2}}{\sqrt{15}+3\sqrt{2}}*\frac{\sqrt{15}-3\sqrt{2}}{\sqrt{15}-3\sqrt{2}}\\\\=\frac{7\sqrt{30}-21}{10-3}-\frac{2\sqrt{30}-10}{6-5}-\frac{3\sqrt{30}-18}{15-18}\\\\=\sqrt{30}-3-2\sqrt{30}+10+\sqrt{30}-6\\\\=1


    tep explanation:

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