25. Find the value of p for which the points (-5, 1), (1, p) and (4, -2) are collinear.​

Question

25. Find the value of p for which the points (-5, 1), (1, p)
and (4, -2) are collinear.​

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Serenity 4 weeks 2021-09-04T01:24:01+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-04T01:25:09+00:00

    Answer:

    answer attached in photo

    0
    2021-09-04T01:25:38+00:00

    Step-by-step explanation:

    If the points are collinear then the area will be 0.

    Area=0

     0 = \frac{1}{2} (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2))

    =

    0=½[(-5)(p-(-2))+1(-2-1)+4(1-p)]

    0=½[(-5)(p+2)+(-3)+4(1-p)]

    0=½[-5p-10-3+4-4p]

    0=-9p-13+4

    0=-9p-9

    9=-9p

    9/-9=

    -1=p.

    Hope helps u.

    Pls mark as brainliest.

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