## 25. The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair. Find the cost of each​

Question

25. The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair.
Find the cost of each​

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3 weeks 2021-08-19T07:17:05+00:00 2 Answers 0 views 0

## Answers ( )

1. Let,cost of one chair be x

cost of one table will be x+40

Then,

cost of 2 tables + cost of 3 chairs = 360

2(x+40)+x=360

2x+80+x=360

3x+80=360

3x=360-80

3x=240

x=240/3

x=80

## Therefore,

### Cost of 1 table = 120

• The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair. Find the cost of each ?

• a) The price of 2 tables and 3 chairs is 360.
• b) A table costs 40 more than the chair.

{ According to question & given }

• Let, x be the cost of table & y be the cost of chair .

Hence, { From ( a ) }

• 2x + 3y = 360 …… ( 1 )

{ From given ( b ) }

• x = y + 40 …… ( 2 )
• x – y = 40 …… ( 3 )

Multiply eq. ( 3 ) by 2

• 2x – 2y = 80 …… ( 4 )

Subtract eq. ( 4 ) eq. ( 1 )

2x + 3y = 360

– ( 2x – 2y = 80 )

__________________

5y = 280

y = 280/5

y = 56

Put value of y in eq. ( 2 )

• x = y + 40
• x = 56 + 40
• x = 96

Hence cost of one table is unit 96 & cost of one chair is unit 56.