25. The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair. Find the cost of each​

Question

25. The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair.
Find the cost of each​

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Peyton 3 weeks 2021-08-19T07:17:05+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-19T07:18:24+00:00

    Let,cost of one chair be x

    cost of one table will be x+40

    Then,

    cost of 2 tables + cost of 3 chairs = 360

    2(x+40)+x=360

    2x+80+x=360

    3x+80=360

    3x=360-80

    3x=240

    x=240/3

    x=80

    Therefore,

    Cost of 1 chair = 80

    Cost of 1 table = 120

    0
    2021-08-19T07:18:29+00:00

    {  \sf{ \underline{ \red{ \underline{Question}}}} : -  }

    • The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair. Find the cost of each ?

    {  \sf{ \underline{ \red{ \underline{Given}}}} : -  }

    • a) The price of 2 tables and 3 chairs is 360.
    • b) A table costs 40 more than the chair.

    {  \sf{ \underline{ \red{ \underline{Solution}}}} : -  }

    { According to question & given }

    • Let, x be the cost of table & y be the cost of chair .

    Hence, { From ( a ) }

    • 2x + 3y = 360 …… ( 1 )

    { From given ( b ) }

    • x = y + 40 …… ( 2 )
    • x – y = 40 …… ( 3 )

    Multiply eq. ( 3 ) by 2

    • 2x – 2y = 80 …… ( 4 )

    Subtract eq. ( 4 ) eq. ( 1 )

    2x + 3y = 360

    – ( 2x – 2y = 80 )

    __________________

    5y = 280

    y = 280/5

    y = 56

    Put value of y in eq. ( 2 )

    • x = y + 40
    • x = 56 + 40
    • x = 96

    Hence cost of one table is unit 96 & cost of one chair is unit 56.

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