## 25. The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair. Find the cost of each

Question

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## Answers ( )

Let,cost of one chair be x

cost of one table will be x+40

Then,

cost of 2 tables + cost of 3 chairs = 360

2(x+40)+x=360

2x+80+x=360

3x+80=360

3x=360-80

3x=240

x=240/3

x=80

## Therefore,

## Cost of 1 chair = 80

## Cost of 1 table = 120

2tables and3chairs is360, but a table costs40more than the chair. Find the cost of each ?2tables and3360.40more than the chair.{

According to question&given}xbe the cost of table &ybe the cost of chair ., {HenceFrom1){

Fromgiven( b ) }2)3)Multiplyeq. (3) by24)Subtracteq. (4) eq. (1)2x + 3y = 360

– ( 2x – 2y = 80 )

__________________

5y = 280

y = 280/5

y =

56Put valueofyineq. (2)96Henceunit96& costof one chair isunit56.