(26. द्विघाती सूत्र से मूल ज्ञात कीजिए। 3×2-5x + 2 = 0​

Question

(26. द्विघाती सूत्र से मूल ज्ञात कीजिए।
3×2-5x + 2 = 0​

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Elliana 3 weeks 2021-11-06T23:07:37+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-06T23:09:21+00:00

    Step-by-step explanation:

    3x²-5x + 2 = 0

    3x²-3x-2x+2=0

    3x(x-1)-2(x-1)=0. p=3×2

    (x-1)(3x-2)=0. =6

    (x-1)=0 or (3x-2)=0. s=-5

    x=1 or 3x=2. no.=-3,-2

    x=1 or x=2/3

    the roots of equation is 1 and 3/2.

    0
    2021-11-06T23:09:24+00:00

    3x²-5x+2

    =3x²3x2x+2

    =3x(x-1)+2(x-1)

    =(x-1)(3x+2)

    Either

    x-1=0

    =>x=1

    Or

    3x+2=0

    =>3x= -2

    =>x= -2/3

    Hope it helps...

    please mark as brainliest....

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