26. The population of a town increases 10% annually. If its present will be its population after 2 years?​

Question

26. The population of a town increases 10% annually. If its present
will be its population after 2 years?​

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Hailey 1 month 2021-08-20T16:59:33+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-20T17:01:00+00:00

    Present population = 60000
    (As you haven’t given the present population, I’ve assumed it to be 60,000 because I have a question like this and in that the present population is 60,000. If it is wrong, u can substitute the value of 60000 and write the value according to your book.)

    For 1st year,
    Increase = 10%
    = 10% of 60000
    = 10/100 x 60000
    = 6000
    Therefore, population after 1st year = 60000 + 6000 = 66000

    For 2nd year,
    Increase = 10%
    = 10% of population after 1st year
    = 10/100 x 66000
    = 6600
    Therefore, population of the town after 2nd year = 66000 + 6600
    = 72600

    Hence, population of town after 2 years = 72,600

    Please mark as brainliest. Hope this helps!

    0
    2021-08-20T17:01:12+00:00

    Answer:

    Mate u have not given present population.

    How would I calculate??

    Step-by-step explanation:

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