## 26. The population of a town increases 10% annually. If its present will be its population after 2 years?

Question

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## Answers ( )

Present population = 60000

(As you haven’t given the present population, I’ve assumed it to be 60,000 because I have a question like this and in that the present population is 60,000. If it is wrong, u can substitute the value of 60000 and write the value according to your book.)

For 1st year,

Increase = 10%

= 10% of 60000

= 10/100 x 60000

= 6000

Therefore, population after 1st year = 60000 + 6000 = 66000

For 2nd year,

Increase = 10%

= 10% of population after 1st year

= 10/100 x 66000

= 6600

Therefore, population of the town after 2nd year = 66000 + 6600

= 72600

Hence, population of town after 2 years = 72,600

Please mark as brainliest. Hope this helps!

Answer:Mate u have not given present population.

How would I calculate??

Step-by-step explanation: