26400(1+15/100) rays to 2 26400(1+3/20)rays to 2 26400(23/20) how?? ** what is the value of i here **how wil

Question

26400(1+15/100) rays to 2
26400(1+3/20)rays to 2
26400(23/20)
how??
** what is the value of i here
**how will we get 23/20

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Athena 1 month 2021-09-21T23:19:08+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-09-21T23:20:16+00:00

    Answer:

    .Given that,

    AB=1m=100cm,

    l=40cm

    The balancing condition for meter bridge is

    R2

    R1

    =

    100−l

    l

    R1=R2(

    100−l

    l

    )

    R1=R2(

    100−40

    40

    )

    R1=R2(

    60

    40

    )=

    6

    4

    R2…….(1)

    When R2 is shunted by a resistance of 10 , l = 50 cm hence,

    R1−10=R2(

    100−50

    50

    )

    R1−10=R2

    6

    4

    R2−10=R2 ……..from(1)

    2R2=10

    R2=5Ω

    Using this in (1), we get

    R1=(

    6

    4

    )5=

    3

    10

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