3x+4y=10 We know that standard form of straight line ax+by+c=0, perpendicular distance is = ∣∣∣∣∣​a2+b2​ax+by+c​∣∣∣∣∣​

Question

3x+4y=10

We know that standard form of straight line ax+by+c=0, perpendicular distance is = ∣∣∣∣∣​a2+b2​ax+by+c​∣∣∣∣∣​

Given point is (4,5)

Therefore perpendicular distance = ∣∣∣∣∣​32+42​4×3+4×5−10​∣∣∣∣∣​

⇒522​

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toppr

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Allison 1 month 2021-08-14T15:45:18+00:00 2 Answers 0 views 0

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    2021-08-14T15:46:21+00:00

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    thanks brother or sister it’s helpful

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    2021-08-14T15:46:59+00:00

    Answer:

    Thanks this is helpful……

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