3) Find the smallest number which when diminished by 7 is divisible by 12, 16, 18, 21 and 28.​

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3) Find the smallest number which when diminished by 7 is divisible by 12, 16, 18, 21 and 28.​

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Savannah 3 days 2021-09-09T14:04:41+00:00 1 Answer 0 views 0

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    2021-09-09T14:05:42+00:00

    Answer:

    First find the smallest number divisible by 12,16,18,21 and 28. It is the LCM of these numbers. So the number will be 1008+7 = 1015.

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