3. From the curve y = |x|, draw (i) y= |x – 11 + 1 (ii) y = x + 11 – 1 (iii) y = x + 2 – 3​

Question

3. From the curve y = |x|, draw (i) y= |x – 11 + 1 (ii) y = x + 11 – 1
(iii) y = x + 2 – 3​

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Iris 2 weeks 2021-09-13T22:11:29+00:00 1 Answer 0 views 0

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    2021-09-13T22:12:36+00:00

    Answer:

    y=x  

    3

    +x−2…(i)

    y=4x−1….(ii)

    Slope of tangent to the curve (i)

    dx

    dy

    ​  

    =3x  

    2

    +1

    slope of tangent at point (α,β) is

    ​  

     

    dx

    dy

    ​  

     

    ​  

     

    (α,β)

    ​  

    =3α  

    2

    +1…(iii)

    Given, tangent of curve (i) is parallel to line (ii)

    ∴ Slope of line (ii) is 4

    ∴ From Eq(iii) we get

    3α  

    2

    +1=4⇒α=±1

    ∴(α,β) lie on curve (i)

    β=(±1)  

    2

    +(±1)−2⇒β=0,−4

    ∴ Points are (1,0) and (−1,−4)

    Step-by-step explanation:

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