3. If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is: Question 3. If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is: in progress 0 Math Elliana 6 months 2021-12-10T17:45:56+00:00 2021-12-10T17:45:56+00:00 2 Answers 0 views 0

## Answers ( )

Step-by-step explanation:Applyinglogbothsidesweget## → Solution:

(0.2)x = 2.

Taking log on both sides

log (0.2)x = log 2.

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (2/10) = 0.3010.

x [log 2 – log 10] = 0.3010.

x [log 2 – 1] = 0.3010,[since log 10=1].

x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].

x[-0.699] = 0.3010.

x = 0.3010/-0.699.

x = -0.4306….

x = -0.4 (nearest tenth)

## Answer: (c)