3. The two adjacent sides of a rectangle are 3a – b and 6b – a. Find its perimeter. 4. Find the perimeter of a triangle whose sides are

Question

3. The two adjacent sides of a rectangle are 3a – b and 6b – a. Find its perimeter.
4. Find the perimeter of a triangle whose sides are 2y + 3z, 2 – y, 4y – 22.
5. Subtract:​

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Genesis 1 month 2021-08-16T06:56:45+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-16T06:58:04+00:00

    Answer:

    3)P=2[(3a-b)+(6b-a) ]

    =2(2a+5b)

    4a +10b is the answer…

    Step-by-step explanation:

    4)(2y+3z) + (2-y) + (4y -22)

    =(2y -y +4y)+(3z)+(2-22)

    =5y+3z-20 is the final answer

    0
    2021-08-16T06:58:22+00:00

    Answer:

    3 answer

    perimeter of rectangle= 2(l+b)

    =2(3a-b+6b-a)

    =2(2a+5b)

    =4a+10b

    Step-by-step explanation:

    4 answer

    perimeter of triangle=sum of all sides

    =2y+3z+2-y+4y-22

    =5y+3z-20

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