4/3 cot²30° + 3 sin²30° – 2 cosec²60° – 3/4 tan²30° karo Yaar koi to solve-​

Question

4/3 cot²30° + 3 sin²30° – 2 cosec²60° – 3/4 tan²30°

karo Yaar koi to solve….​

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Lydia 2 weeks 2021-09-10T09:49:08+00:00 2 Answers 0 views 0

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    0
    2021-09-10T09:50:09+00:00

    \huge{\bold{\star{\fcolorbox{black}{lightgreen}{Bonjour}}}}

    \huge\mathfrak\blue{Answer:-}

     <font color = white >

     \cot 30 =  \sqrt{3}  \\  \sin \: 60 =  \frac{ \sqrt{3} }{2}  \\  \cos \sec \: 60 =  \frac{2}{ \sqrt{3} }  \\  \tan \: 30 =  \frac{1}{ \sqrt{3} }

     \frac{4}{3}  \cot^{2} 30 + 2 \sin ^{2} 60 - 2 \cos\sec^{2} 60 -  \frac{3}{4}  \tan^{2} 30 \\  =  \frac{4}{3}  \times ( { \sqrt{3} })^{2}  + 2 \times ( \frac{3}{2})^{2}  - 2 \times  \frac{2}{ \sqrt{3} })^{2}  -  \frac{3}{4}  \times ( \frac{1}{ \sqrt{3} } ) ^{2}  \\  =  \frac{4}{3}  \times 3 + 2 \times  \frac{3}{4}  - 2 \times  \frac{4}{3}  -  \frac{3}{4}  \times  \frac{1}{3}  \\  = 4 +  \frac{3}{2}  -  \frac{8}{3}  -  \frac{1}{4}  \\  = 4 + 18 - 32 -  \frac{3}{12}  \\  = 22 -  \frac{35}{12}  \\  =  \frac{ - 13}{12}

    Hope it helps you ƪ(˘⌣˘)ʃ

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    0
    2021-09-10T09:50:11+00:00

    Answer:

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