4/3 cot²30° + 3 sin²30° – 2 cosec²60° – 3/4 tan²30° karo Yaar koi to solve-​

Question

4/3 cot²30° + 3 sin²30° – 2 cosec²60° – 3/4 tan²30°

karo Yaar koi to solve….​

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Sadie 1 week 2021-09-10T02:06:08+00:00 2 Answers 0 views 0

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    0
    2021-09-10T02:07:26+00:00

    Answer:

    answer for the given problem is given

    0
    2021-09-10T02:07:45+00:00

    43cot230+3sin260−2cosec260−34tan230Puttingthevaluesofsin60,cot30,cosec60tan30weget=43(3)−−√2+3(3√2)2−2(23√)2−34(13√)2=4+94−83−14=4+2−83=6−83=(18−8)3=103

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