4( sin^30° + cos* 60°)-sin? 60° – cos? 45° ) +_ tan 60​

Question

4( sin^30° + cos* 60°)-sin? 60° – cos? 45° ) +_ tan 60​

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Mia 1 week 2021-09-10T10:23:05+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-10T10:24:12+00:00

    Answer:

    4(sin⁴30°cos⁴60°)-2/3(sin²60°-cos²45°)+1/2tan²60°

    =4{(1/2)⁴(1/2)⁴}-2/3{(√3/2)²-(1/√2)²}+1/2(√3)²

    =4(1/16)(1/16)-2/3(3/4-1/2)+3/2

    =1/64-2/3(1/4)+3/2

    =1/64+3/2-1/6

    =97/64-1/6

    =259/192

    Step-by-step explanation:

    0
    2021-09-10T10:24:55+00:00

    Correct Question :

    ★ 4(sin⁴30°cos⁴60°) -2/3(sin²60°-cos²45°)+ 1/2tan²60°

    → 4{(1/2)⁴(1/2)⁴}-2/3{(√3/2)²-(1/√2)²}+1/2(√3)²

    → 4(1/16)(1/16)-2/3(3/4-1/2)+3/2

    → 1/64-2/3(1/4)+3/2

    → 1/64+3/2-1/6

    → 97/64 – 1/6

      \longrightarrow\sf \large \dfrac{259}{192}

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