42.The sum of square of two consecutive positive integers exceeds their product by 91 find the integers ? (1 Point) 9

Question

42.The sum of square of two consecutive positive integers exceeds their product by 91 find the integers ?

(1 Point)

9,10

10,11

12,13

11,12

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Lyla 4 months 2022-01-06T17:08:46+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-01-06T17:10:34+00:00

    Answer:

    9,10

    Step-by-step explanation:

    I can’t explain it because my mother will not

    0
    2022-01-06T17:10:42+00:00

    Answer:

    9,10

    Step-by-step explanation:

    Let the numbers be x and x+1

    x^2 + (x+1)^2 = x(x+1) +91

    x^2 + x^2 + 2x +1 = x^2 + x +91

    x^2+x-90 = 0

    x^2-9x+10x-90=0

    x(x-9)+10(x-9)=0

    x=9 or -10

    Since x is positive so x=9

    Second number will x+1 = 10

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