## 42.The sum of square of two consecutive positive integers exceeds their product by 91 find the integers ?￼ (1 Point) 9

Question

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## Answers ( )

Answer:9,10

Step-by-step explanation:I can’t explain it because my mother will not

Answer:9,10

Step-by-step explanation:Let the numbers be x and x+1

x^2 + (x+1)^2 = x(x+1) +91

x^2 + x^2 + 2x +1 = x^2 + x +91

x^2+x-90 = 0

x^2-9x+10x-90=0

x(x-9)+10(x-9)=0

x=9 or -10

Since x is positive so x=9

Second number will x+1 = 10