5. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the ext

Question

5. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m
and base radius 6 m? Assume that the extra length of material that will be required for
stitching margins and wastage in cutting is approximately 20cm (Use Tt= 3.14).
meaning

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Gabriella 1 month 2021-08-12T17:04:06+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-12T17:05:26+00:00

    \large{\mathcal{\underline{\:\:\:\:\:\:Solution\:\:\:\:\:\:\:\:}}}

    Hight of conical tent,h=8 m

    Radius of base of tent,r=6 m

    Stant height of tent, \sf{l^2=r^2+h^2}

    __________________________

    \sf{Here,}

    \large\sf{l^2=(6^2+8^2)}

    \large\sf{→l^2=(36+64)}

    \large\sf{→l^2=100}

    \large\sf{→l=√100}

    \large\sf{→l=10}

    __________________________

    \sf{Again,}

    CSA of conical tent,

    \large\sf{πrl}

    \large\sf{=3.14×6×10}

    \large\sf{=188.4\:m^2}

    __________________________

    Let the length of tarpaulin sheet required be L

    As, 20 cm will be wasted,therefore,

    Effective length will be (L – 0.2 m)

    Effective length will be (L – 0.2 m)Breadth of tarpaulin = 3 m (given)

    _________________________

    \large\sf{Area\:of\:sheet\:=CSA\:of\:tent}

    \large\sf{[(L-0.2)×3]=188.4}

    \large\sf{L-0.2=\dfrac{188.4}{3}}

    \large\sf{L-0.2=62.8}

    \large\sf{L=62.8+0.2}

    \large\sf{L=63}

    Therefore, the length of the tarpaulin required is 63 m.

    0
    2021-08-12T17:05:31+00:00

    Answer:

    h = Height of tent = 8 m

    r = Base radius = 6 m

    Therefore,

    l=

    r

    2

    +h

    2

    =10 m

    Curved surface area of the cone = πrl=3.14×6×10 m

    2

    Therefore, length of 3 m wide tarpaulin required =

    3

    3.14×6×10

    =62.8 m

    Extra length required = 0.2 m

    Therefore, total length required = 63 m

    Step-by-step explanation:

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