5 years ago a man was 7 times as old as his son after five years he will thrice as old as his son. find their present ages.​

Question

5 years ago a man was 7 times as old as his son after five years he will thrice as old as his son. find their present ages.​

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Skylar 4 days 2021-09-13T17:54:32+00:00 2 Answers 0 views 0

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    0
    2021-09-13T17:55:39+00:00

    Answer:

    Sons age 5 years ago=x father’s age = 7x

    their present age = x+5 and 7x+5 resp

    Sons age 5 years hence = x+10(since x is sons age 5 years ago from present age and we are talking of his age 5 years hence from his present age so 5+5=10)

     

    fathers age 5 years hence =3(x+10)

    hence the fathers present age will be 3(x+10)-5

    also fathers present age =7x+5

    therefore 7x+5=3(x+10)-5

    7x+5=3x+30-5

    7x-3x=25-5

    4x=20

    x=5

     

    So, son’s present age = 10years and fathers, present age = 40 years

    Step-by-step explanation:

    pls mark it as brainliest

    0
    2021-09-13T17:56:06+00:00

    Step-by-step explanation:

    Let Five years ago the age of son be x years and age of father be 7x years

    Present age of son =x+5

    Present age of father =7x+5

    5 years later their age will (x+10) and (7x+10)

    ∴7x+10=3(x+10)

    7x−3x=20

    4x=20

    x=5

    So, the present age of son=x+5=5+5=10years

    and the present age of father=7x+5=35+5=40years

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