7. For an integer n, n! =n(n-1)(n-2)-.3, 2, 1. Then 1!+2!+3!+-.+100! When divided by 5 leaves remainderans 3 ​

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7. For an integer n, n! =n(n-1)(n-2)…..3, 2, 1. Then
1!+2!+3!+…..+100! When divided by 5 leaves remainderans 3

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Ximena 2 days 2021-09-13T21:21:05+00:00 1 Answer 0 views 0

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    2021-09-13T21:22:27+00:00

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