80. समीकरण 6(x {}^{2} + 1 ) = 13x के मूल है।​

Question

80.
समीकरण
6(x {}^{2}  + 1 ) = 13x
के मूल है।​

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Emery 1 month 2021-08-17T14:46:54+00:00 1 Answer 0 views 0

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    2021-08-17T14:48:22+00:00

    \red{\bold{\underline{\underline{QUESTION:-}}}}

    6 ({x}^{2}  + 1) = 13x

    \huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar

    6( {x}^{2}  + 1) = 13

    6 {x}^{2}  + 6 = 13

    6 {x}^{2}  = 13 - 6

    6 {x}^{2}  = 7

    x = ±\sqrt{ \frac{7}{6} }

    Hope it helps you..!!!

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