9x^2+ 49y^2 + 42 xy, when x = 3 and y=1 find the value​

Question

9x^2+ 49y^2 + 42 xy, when x = 3 and y=1 find the value​

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Savannah 1 month 2021-08-20T05:41:42+00:00 2 Answers 0 views 0

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    0
    2021-08-20T05:43:09+00:00

    Answer:

    256

    Step-by-step explanation:

    =9(3)^2+49(1)^2+42(3)(1)

    =81+49+126

    =256

    hope you understand

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    0
    2021-08-20T05:43:19+00:00

    Answer:

    9*9+49*1+42*3*1=81+49+126=256

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