Find the smallest number which when divided by 32, 72 and 80 leaves remainder 14 in each case Question Find the smallest number which when divided by 32, 72 and 80 leaves remainder 14 in each case in progress 0 Math Isabella 3 weeks 2021-10-04T01:54:37+00:00 2021-10-04T01:54:37+00:00 1 Answer 0 views 0

## Answers ( )

Answer:1454

Step-by-step explanation:L. C. M of 32,72,80= 2×2×2×2×2×9×5

= 1440

It leaves remainder 14 in each case

then 1440+14 = 1454