## A 115 m long and 64 m broad lawn has two roads inside it at right angles, one 2 m wide, running parallel to its length, and the other 2

Question

A 115 m long and 64 m broad lawn has two roads inside it at right angles, one 2 m
wide, running parallel to its length, and the other 2.5 wide, running parallel to its
breadth. Find the cost of gravelling the roads at 4.60 per m2.​

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1 month 2021-08-13T07:23:54+00:00 2 Answers 0 views 0

sorry I am weak in math plzz support me then I answered you with struggle

= Rs 23,100

Step-by-step explanation:

Length of the rectangular field, CD = 115 cm

Breadth of the rectangular field, BC = 64 m

∴ Area of the rectangular lawn ABCD = 115 m × 64 m = 7360 m2

Area of the road PQRS = 115 m × 2 m = 230 m2

Area of the road KLMN = 64 m × 2.5 m = 160 m2

Clearly, the area of EFGH is common to both the two roads.

∴ Area of EFGH = 2 m × 2.5 m = 5 m2

∴ Area of the roads = Area (KLMN) + Area (PQRS) − Area (EFGH)

= (230 m2 + 160 m2) − 5 m2 = 385 m2

Rate of gravelling the roads = Rs 60 per m2

∴ Total cost of gravelling the roads = Rs (385 × 60)

= Rs 23,100