## निम्न में से क्या द्विघात समीकरण है? (a) x2 -79= x2 +9x+1 (b) 12×2 -7=0 (c) 3×2 +11x+14=x(3x+5x) (d) -x2

Question

निम्न में से क्या द्विघात समीकरण है?
(a) x2
-79= x2
+9x+1 (b) 12×2
-7=0
(c) 3×2
+11x+14=x(3x+5x) (d) -x2
+11x-18=0

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5 months 2022-01-06T17:21:48+00:00 2 Answers 0 views 0

a)Givenequation:x2−79=x2+9x+1

/* subtract bothsides of the equation by x², we get */

\implies x^{2} – 79 – x^{2} = x^{2}+9x+1 – x^{2}⟹x2−79−x2=x2+9x+1−x2

\implies -79 = 9x + 1⟹−79=9x+1

\blue { ( Degree \: of \: the\: equation \:is \: 1 )}(Degreeoftheequationis1)

So, it \:is \:a \: Linear \: equationSo,itisaLinearequation

b) Given \: 12x^{2} – 7 = 0b)Given12x2−7=0

\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)

c) Given \: equation : 3x^{2}+11x+14=x(3x+5x)c)Givenequation:3×2+11x+14=x(3x+5x)

\implies 3x^{2}+11x+14= x\times 8x⟹3×2+11x+14=x×8x

\implies 3x^{2}+10x+14= 8x^{2}⟹3×2+10x+14=8×2

\implies 3x^{2}+10x+14-8x^{2}=0⟹3×2+10x+14−8×2=0

\implies -5x^{2}+10x+14=0⟹−5×2+10x+14=0

\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)

d) Given \: equation : -x^{2}+11x-18 = 0d)Givenequation:−x2+11x−18=0

\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)