A 5cm tall object is placed perpendicular to the principle axis of convex lens of focal length 20 cm . The distance of the object from the l

Question

A 5cm tall object is placed perpendicular to the principle axis of convex lens of focal length 20 cm . The distance of the object from the lens is 30 cm. Calculate the distance of image from the lens

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Audrey 1 month 2021-08-18T03:24:34+00:00 1 Answer 0 views 0

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    0
    2021-08-18T03:25:34+00:00

    Answer:

    According to the question:

    Object distance, u=−12 cm

    Focal length, f=18 cm (since, convex lens)

    Let the Image distance be v.

    By lens formula:

    v

    1

    u

    1

    =

    f

    1

    [4pt]

    v

    1

    −12 cm

    1

    =

    18 cm

    1

    [4pt]

    v

    1

    =

    −12 cm

    1

    +

    18 cm

    1

    [4pt]

    v

    1

    =

    36 cm

    −3+2

    [4pt]

    v

    1

    =−

    36 cm

    1

    [4pt]

    ∴v=−36 cm

    Thus, image is obtained at 36 cm on the same side of the mirror as the object.

    Now,

    Height of object, h

    1

    =5 cm

    Magnification, m=

    h

    1

    h

    2

    =

    u

    v

    Putting values of v and u:

    Magnification m=

    5 cm

    h

    2

    =

    −12 cm

    −36 cm

    5 cm

    h

    2

    =3

    [4pt];

    ⇒h

    2

    =3×5 cm=15 cm

    Thus, the height of the image is 15 cm and the positive sign means the image is virtual and erect.

    Thus virtual, erect and enlarged image is formed.

    Step-by-step explanation:

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18:9+8+9*3-7:3-1*13 = ? ( )