A = [aij] ₂ₓ₃ whose elements are aij = [ i + j ] ² , then A = [ ] – ? Question A = [aij] ₂ₓ₃ whose elements are aij = [ i + j ] ² , then A = [ ] – ? in progress 0 Math Quinn 5 months 2022-01-06T18:33:35+00:00 2022-01-06T18:33:35+00:00 1 Answer 0 views 0

## Answers ( )

Answer:Step-by-step explanation:A = [aij]₂ₓ₃

There are 2 rows and three columns, the possible orders are a₁₁, a₁₂, a₁₃, a₂₁, a₂₂, a₂₃

aij = [ i+j ]²

a₁₁ = [1+1]² = 2² =4

a₁₂ = [1+3]² = 4² = 16

a₁₃ = [1+3]² = 4² = 16

a₂₁ = [2+1]² = 3² = 9

a₂₂ = [2+2]² = 4² = 16

a₂₃ = [2+3]² = 5² =25

A =