A = [aij] ₂ₓ₃ whose elements are aij = [ i + j ] ² , then A = [ ] – ?

Question

A = [aij] ₂ₓ₃ whose elements are aij = [ i + j ] ² , then A = [ ] – ?

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Quinn 5 months 2022-01-06T18:33:35+00:00 1 Answer 0 views 0

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    2022-01-06T18:35:13+00:00

    Answer:

    Step-by-step explanation:

    A = [aij]₂ₓ₃

    There are 2 rows and three columns, the possible orders are a₁₁, a₁₂, a₁₃, a₂₁, a₂₂, a₂₃

    aij = [ i+j ]²

    a₁₁ = [1+1]² = 2² =4

    a₁₂ = [1+3]² = 4² = 16

    a₁₃ = [1+3]² = 4² = 16

    a₂₁ = [2+1]² = 3² = 9

    a₂₂ = [2+2]² = 4² = 16

    a₂₃ = [2+3]² = 5² =25

    A = \left[\begin{array}{ccc}4&16&16\\9&16&25\\\end{array}\right]

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