A and B can finish a peice of work in 16 and 12 days respectively. A started the work and worked at it for 2 days. He was then joined by B .

Question

A and B can finish a peice of work in 16 and 12 days respectively. A started the work and worked at it for 2 days. He was then joined by B . Find the total time taken โ€‹

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Rylee 1 month 2021-09-22T00:46:38+00:00 2 Answers 0 views 0

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    2021-09-22T00:48:25+00:00

    Sorry mam I have no answer

    0
    2021-09-22T00:48:37+00:00

    Answer:

    A’s 1 day work = 1/16

    B’s 1 day work = 1/12

    (As A worked for 2 days alone we’ll find work done by A in 2 days by multiplying his one day work by 2)

    A’s 2 day work = 2x(1/16) =1/8

    Remaining work = 1โ€“1/8 =7/8

    ( Total work is always presumed to be 1 in all such cases )

    Now this remaining work will be done by A and B together .

    (A+B)’s 1 day work = (1/16) + (1/12) = 7/48

    A and B together can do the remaining work in = (7/8)รท(7/48) = 6 days

    Total time taken = 6+2 = 8 days ANS

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