A ball is dropped from a height of 128 m. It bounces back rising to a height of 64 m. Each time it further touches the floor, it rises

Question

A ball is dropped from a height of 128 m. It bounces back rising to
a height of 64 m. Each time it further touches the floor, it rises to the
height of half the height it fell from before the previous bounce. Find
the total distance travelled by the ball.​

in progress 0
Aubrey 2 months 2021-08-12T08:56:05+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-12T08:57:07+00:00

    Hello here your answer

    Step-by-step explanation:

    128 + 64 = 192

    0
    2021-08-12T08:57:52+00:00

    Answer:

    Initial fall

    s

    1

    =

    128

    m

    Next rise and fall

    s

    2

    =

    2

    1

    2

    128

    m

    Next rise and fall

    s

    3

    =

    2

    (

    1

    2

    2

    )

    128

    m

    Next rise and fall

    s

    4

    =

    2

    (

    1

    2

    3

    )

    128

    m

    So total path traveled is

    S

    =

    i

    =

    I

    =

    1

    s

    i

    =

    128

    +

    128

    (

    1

    +

    1

    2

    +

    1

    2

    2

    +

    .

    .

    up to

    )

    =

    128

    +

    128

    (

    1

    1

    1

    2

    )

    =

    128

    +

    128

    (

    1

    1

    2

    )

    =

    3

    128

    =

    384

    m

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