A candidate score 25% maeks and failed by 60 marks while the other candidate got 50% marks and got 40 marks more than the maximum marks requ

Question

A candidate score 25% maeks and failed by 60 marks while the other candidate got 50% marks and got 40 marks more than the maximum marks required to pass..Find the total marks of the examination​

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Peyton 2 months 2021-08-13T11:40:02+00:00 2 Answers 0 views 0

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    0
    2021-08-13T11:41:35+00:00

    Answer:

    Let maximum mark be x and minimum mark be y.

    25% of maximum mark = (25/100)x = x/4 = y-30 …………..(1)

    50% of maximum mark = (50/100)x = x/2 = y+20 ………..(2)

    subtract eqn.(1) from eqn.(2), we get x/4 = 50 or x = 200

    substituting value of x in eqn.(1), we get y = 80

    hence maximum mark is 200 and minimum mark is 80

    Step-by-step explanation:

    please mark me as brainly

    0
    2021-08-13T11:41:39+00:00

    Answer:

    Minimum passing marks are 80.

    Step-by-step explanation:

    Let the maximum marks be ‘x’.

    Then, according to the question.

    (25 % of x) + 30 = (50 % of x) – 20

    ⇒ x/4 + 30 = x/2 – 20

    ⇒ (x/4) – (x/2) = – 20 – 30

    ⇒ (x – 2x)/4 = – 50

    ⇒ – x/4 = – 50

    ⇒ – x = – 200  

    ⇒ x = 200

    So, the maximum marks are 200.

    Minimum passing marks are = x/4 + 30

    = 200/4 + 30

    = 50 + 30

    = 80 marks

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