a. Find two numbers whose sum is 48 and difference is 10? b. The sum of two numbers is 34 and their difference is 8 which are the

Question

a. Find two numbers whose sum is 48 and difference is 10?
b. The sum of two numbers is 34 and their difference is 8 which are the numbers ?​

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Delilah 1 month 2021-08-12T15:15:44+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-12T15:16:53+00:00

    Answers

    (a) Let the sum of x + y = 48 (Equation 1)

    and, the difference x – y = 10 (Equation 2)

    Firstly, let me take the value of Equation 2 as x

    ∴ x = 10 + y

    Now, writing the first Equation

    x + y = 48

    We have the value of x i.e 10 + y

    ∴ Subsisting Values

    ⟹ 10 + y + y = 48

    ⟹ 10 + 2y = 48

    ⟹ 2y = 48 – 10

    ⟹ 2y = 38

    ⟹ y = 19

    Now, let’s substitute Equation 1

    ⟹ x + y = 48

    ⟹ x + 19 = 48

    ⟹ x = 48 – 19

    ⟹ x = 29

    Thus, Proved also

    x + y = 48

    ⟹ 29 + 19 = 48

    x – y = 10

    ⟹ 29 – 19 = 10

    (b) Let the sum of x + y = 34 (Equation 1)

    and, the difference x – y = 8 (Equation 2)

    Firstly, let me take the value of Equation 2 as x

    ∴ x = 8 + y

    Now, writing the first Equation

    x + y = 34

    We have the value of x i.e 8 + y

    ∴ Subsisting Values

    ⟹ 8 + y + y = 34

    ⟹ 8 + 2y = 34

    ⟹ 2y = 34 – 8

    ⟹ 2y = 26

    ⟹ y = 13

    Now, let’s substitute Equation 1

    ⟹ x + y = 34

    ⟹ x + 13 = 34

    ⟹ x = 34 – 13

    ⟹ x = 21

    Thus, Proved also

    x + y = 34

    ⟹ 21 + 13 = 34

    x – y = 10

    ⟹ 21 – 13 = 8

    0
    2021-08-12T15:16:59+00:00

    Answer:

    345

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