a. Find two numbers whose sum is 48 and difference is 10? b. The sum of two numbers is 34 and their difference is 8 which are the

Question

a. Find two numbers whose sum is 48 and difference is 10?
b. The sum of two numbers is 34 and their difference is 8 which are the numbers ?​

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Kennedy 1 month 2021-08-12T14:08:37+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-12T14:10:14+00:00

    Step-by-step explanation:

    a. sum of two numbers =48

    difference between them =10

    let one number be x

    second number =x+10

    so, x+x+10 =48

    2x+10 =48

    2x =48-10

    2x =38

    x=38/2

    x=19

    one number =x

    =19

    second number =x+10

    =19+10

    =29

    b. sum of two numbers =34

    difference between them =8

    let one number =x

    second number =x+8

    so,

    x+x+8=34

    2x+8=34

    2x=34-8

    2x=26

    x=26/2

    x=13

    one number =x

    =13

    second number =x+8

    =13+8

    =21

    0
    2021-08-12T14:10:25+00:00

    Answer:

    (i)solve :- let the two no. be x and y

    given :- x+y=48 and x-y=10

    (x+y)+(x-y)=48+10

    x+y+x-y=58

    2x=58

    x=58÷2

    x=29 answer

    29+y=48

    y=48-29

    y=19 answer

    so, the two no. will be 29 and 19

    solve 2nd question through this solution

    the answer will be 21 and 13 .

    Hope it will be helpful

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