a fraction before 1/ 3 when 1 is substance for the numerator and its become one1/4 when 8 is added to it denominator find the faction​

Question

a fraction before 1/ 3 when 1 is substance for the numerator and its become one1/4 when 8 is added to it denominator find the faction​

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Lydia 1 month 2021-08-12T10:07:20+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-12T10:08:22+00:00

    AnswEr :

    • The fraction is 5/12.

    Given :

    • A fraction becomes 1/3 when 1 is subtracted from the numerator.

    • It becomes 1/4 when 8 is added to the denominator.

    To Find :

    • The Fraction.

    SoluTion :

    Let,

    • Numerator = x

    • Denominator = y

    Fraction = x/y

    According to question :

    • x – 1/y = 1/3

    3x y = 3 ...i)

    • x/y + 8 = 1/4

    4x y = 8 ...ii)

    Subtracting equation i) from equation ii) , We get

    x = 5 ...iii)

    Putting this value in equation i) , We get

    15 y = 3

    y = 12

    Hence, the fraction is 5/12.

    _____________________

    0
    2021-08-12T10:08:31+00:00

    Given :-

    • A fraction becomes 1/3 when 1 is subtracted for the numerator and its become one 1/4 when 8 is added to its denominator

    To find :-

    • Required fraction

    Solution :-

    Let the required fraction be x/y

    • A fraction becomes ⅓ when 1 is subtracted for the numerator

    → x – 1/y = ⅓

    → 3(x – 1) = y

    → 3x – 3 = y

    → 3x – y = 3 ——(i)

    • A fraction becomes one 1/4 when 8 is added to its denominator

    → x/y + 8 = ¼

    → 4x = y + 8

    → 4x – y = 8 —–(ii)

    Subtract both the equations

    → (3x – y) – (4x – y) = 3 – 8

    → 3x – y – 4x + y = – 5

    → 3x – 4x = – 5

    → – x = – 5

    → x = 5

    Put the value of x in equation (i)

    → 3x – y = 3

    → 3 × 5 – y = 3

    → 15 – y = 3

    → y = 15 – 3

    → y = 12

    Hence,

    • Required fraction
    • Numerator/Denominator = x/y = 5/12

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