A= (x:x is a common factor of 12 and 18}
B=(x:x = n²-n where nEN, n<5 ) hen
find h(AUB} and CANB).​

Question

A= (x:x is a common factor of 12 and 18}<br />B=(x:x = n²-n where nEN, n<5 ) hen<br />find h(AUB} and CANB).​

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Isabelle 8 months 2021-10-03T09:08:11+00:00 1 Answer 0 views 0

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    2021-10-03T09:09:19+00:00

    Answer:

    set A { 1 2 3 6 }

    to form se B let n be 1, 2, 3 ,4 (as n<5 and natural numbers N starts from 1 )

    as x = n^2 – n, put all the four values of n and get corresponding values of x

    therefore values of x are 1^2 – 1 = 0, 2^2 – 2 = 2,

    3^2 – 3 = 6 and 4^2 – 4 = 12

    set B= { 0 2 6 12 }

    A ∪ B = { 0 1 2 3 6 12 }

    n (A ∪ B) = 6

    2nd part of the question is not clear

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