A is twice old as B. five years ago A was three times as old as B.find their present ages​

Question

A is twice old as B. five years ago A was three times as old as B.find their present ages​

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Audrey 2 weeks 2021-09-14T19:47:37+00:00 2 Answers 0 views 0

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    0
    2021-09-14T19:48:48+00:00

    Let B’s age be x yrs.

    So, A’s age = 2x yrs.

    5 yrs ago,

    B’s age = (x-5) yrs.

    A’s age = (2x-5) yrs.

    According to condition,

    3 times B’s age = A’s age.

    3(x-5) = 2x-5

    or, 3x-15 = 2x-5

    or, 3x-2x = -5+15

    or, x = 10

    So, B’s present age = x yrs = 10 yrs.

    And A’s present age= 2x yrs = 20 yrs.

    Hence, their present ages are 20 yrs and 10 yrs respectively.

    0
    2021-09-14T19:49:33+00:00

    Answer: So ages of A & B are 20 & 10 years respectively.

    Step-by-step explanation: Let the ade of A be a and B be b.


    a = 2b……….(1)


    Five years ago


    A’s age was a-5 and B’s age was b-5


    a-5 = 3(b-5)


    a-5 = 3b -15………(2)

    We have to solve two linear equations (1) & (2)


    Substituting value of a =2b in (2)


    2b -5 = 3b – 15


    b = 10 & a = 20


    So ages of A & B are 20 & 10 years respectively.

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