A is twice old as B. five years ago A was three times as old as B.find their present ages Question A is twice old as B. five years ago A was three times as old as B.find their present ages in progress 0 Math Audrey 2 weeks 2021-09-14T19:47:37+00:00 2021-09-14T19:47:37+00:00 2 Answers 0 views 0

## Answers ( )

Let B’s age be x yrs.

So, A’s age = 2x yrs.

5 yrs ago,

B’s age = (x-5) yrs.

A’s age = (2x-5) yrs.

According to condition,

3 times B’s age = A’s age.

3(x-5) = 2x-5

or, 3x-15 = 2x-5

or, 3x-2x = -5+15

or, x = 10

So, B’s present age = x yrs = 10 yrs.

And A’s present age= 2x yrs = 20 yrs.

Hence, their present ages are 20 yrs and 10 yrs respectively.

Answer: So ages of A & B are 20 & 10 years respectively.Step-by-step explanation: Let the ade of A be a and B be b.

a = 2b……….(1)

Five years ago

A’s age was a-5 and B’s age was b-5

a-5 = 3(b-5)

a-5 = 3b -15………(2)

We have to solve two linear equations (1) & (2)

Substituting value of a =2b in (2)

2b -5 = 3b – 15

b = 10 & a = 20

So ages of A & B are 20 & 10 years respectively.