. A man is 4 times as old as his son. After 32 years, he will be only twice as old as his son. Find their present age? ​

Question

. A man is 4 times as old as his son. After 32 years, he will be only twice as old as his son. Find their present age?

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Emery 1 month 2021-08-18T14:44:29+00:00 1 Answer 0 views 0

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    2021-08-18T14:45:31+00:00

    Answer:

    let the present age of father be x and the son be y.

    Now, x = 4y ———- (1)

    After 16 years,


    age of father will be x+ 16

    age of son will be y +16

    Therefore, x + 16 = 2( y + 16)


     

    x + 16 = 2y + 32

    x = 2y + 16

    or 4y = 2y + 16 {Using equation (a)}

    2y = 16

    y = 8

    Plugging back the value of y in equation (1), we get:

    x = 4*8 = 32

    Hence, the present age of father is 32 years and present age of son is 8 year

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