a nber consists of two digits whose whose sum is 9 if 27 is subtracted from the number it’s digits are in the reversed find the number​

Question

a nber consists of two digits whose whose sum is 9 if 27 is subtracted from the number it’s digits are in the reversed find the number​

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Margaret 1 month 2021-08-17T21:09:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-17T21:10:44+00:00

    Assume Z is the Numer and it was a two digit number so,

    Z = x+10y

    x + y = 9

    Z – 27 = 10x + y

    Z = 10x + y + 27

    10x + y + 27 = x + 10y

    27 = x + 10y -10x -y

    9y -9x = 27

    9(y-x) = 27

    y – x = (27/9) = 3

    x + y = 9

    Add above two

    2y = 12

    y = 6

    x + y = 9

    x + 6 = 9

    x = 3

    Z = 3 + (10*6)

    Z = 3 + 60 = 63

    Z = 63

    Hope the above equation will solve many problem by just passing different values -:-)

    0
    2021-08-17T21:10:58+00:00

    Step-by-step explanation:

    Answer:

    36 or 63 can be the number

    Step-by-step explanation:

    Assuming

    x as tens digit

    y as ones digit

    Their sum :

    x + y = 9 ….. (i)

    Number formed :

    10x + y

    Interchanging the digits :

    10y + x

    According to the question :

    ➡ (10x + y) – (10y + x) = 27

    ➡ 9x – 9y = 27

    ➡ 9(x – y) = 27

    ➡ x – y = 27/9

    ➡ x – y = 3 ….. (ii)

    Subtracting both the equation :

     \bf \: x + y = 9 \\  { \underline{ \bf{x - y = 3}}} \\  \implies \bf \: 2x = 6 \\  \implies \bf \: x = 3

    Substituting the value of x in equation (i) :

    ➡ x + y = 9

    ➡ 3 + y = 9

    ➡ y = 6

    Hence

    The number can be 10x + y

    or, 10(3) + 6

    or, 36 either 63

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