## a shopkeeper has two pieces of rope having length 120 and 150 cm we want to cut the ropes into pieces of equal length as long as possible wh

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## Answers ( )

factors of 120=2,2,2,3,5

factors of 150=2,3,5,5

common factors=2,3,5

hence, HCF=30

therefore,

possible equal length should cut is 30cm