A small sphere of mass m kg = 2 moving with a velocity u i j m s = − 4 7 / collides with a smooth wall and returns with a velocity v i j m s

Question

A small sphere of mass m kg = 2 moving with a velocity u i j m s = − 4 7 / collides with a smooth wall and returns with a velocity v i j m s = − + 3 / . The magnitude of the impulse received by the ball is

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Piper 1 month 2021-08-12T15:42:59+00:00 1 Answer 0 views 0

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    2021-08-12T15:44:51+00:00

    here, we have to use formula,

    impulse = change in momentum

    impulse = Pf – Pi

    impulse = m(Vf – Vi)


    here, m = 2 kg

    Vf = (-i + 3j ) m/s

    Vi = (4i – 7j) m/s


    now,

    impulse = 2 × ( -i + 3j – 4i + 7j)

    = 2 × ( -5i + 10j)

    =(-10i + 20j ) kg.m/s


    hence, magnitude of impulse = √(10²+20²)

    = 10√5 N.s

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