A straight line cuts the x- axis at P and the y-axis at R. The gradient of the line RP is -3/2 and the line passes through the point (2,3) f

Question

A straight line cuts the x- axis at P and the y-axis at R. The gradient of the line RP is -3/2 and the line passes through the point (2,3) find: (a) the equation of the line RP (b) the intercept on the y-axis (c) the area of triangle ROP,where O is the origin.

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Piper 4 weeks 2021-08-21T12:04:14+00:00 1 Answer 0 views 0

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    2021-08-21T12:05:47+00:00

    Answer:

    eqn of RP y-3 = (-3/2)(x-2)

    2(y-3)=-3(x-2)

    2y-6=-3x+6

    3x+2y-12=0Ans

    For intercept on Y-axis

    put x=0 in the above eqn

    y=6

    For intercept on X-axis

    put y=0 in the above eqn

    you will get x=4

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