algebraic form of arithmetic sequence 1,6,11,16​

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algebraic form of arithmetic sequence 1,6,11,16​

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Mia 1 week 2021-09-14T05:35:56+00:00 1 Answer 0 views 0

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    2021-09-14T05:37:38+00:00

    Answer:

    Tn= 5n-4

    Step-by-step explanation:

    This is an arithmatic progression

    The first term is 1=a, the common difference is 5= d.

    Any term in this sequence can be written as Tn= a+ (n-1)d

    where Tn is nth term, n is the number of term of the series, a is the first term, d is the common difference.

    Tn =1+ (n-1)5

    Tn= 1+ 5n-5

    Tn= 5n-4

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