## Aman Age is three times as his son’s age Ten year ago he was Five times his son’s age find the present ages

Question

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## Answers ( )

SolutionGiven:–Find:–ExplanationLet,A/Ctoquestion,(Aman Age is three times as his son’s age)

==> x = 3y

==> x – 3y = 0

–––––––––––(1)Again,(Ten year ago he was Five times his son’s age)

==> (x – 10) = 5 × (y – 10)

==> x – 5y = -50 + 10

==> x – 5y = -40

––––––––––(2)Subtractequ(1)&equ(2)==> -3y + 5y = 40

==> 2y = 40

==> y = 40/2

==> y = 20

KeepValueofyinequ(1)==> x – 3 × 20 = 0

==> x = 60

Hence_________________Hello, Good Morning….

Aman’s age is three times as his Son’s age. Ten years ago, he was five times his Son’s age. Find their present ages..

## Answer:

Let Aman’s Son’s present age be ‘

x years.Aman’s age =

3xAman’s age 10 years ago =

(x – 10) years.Aman’s age 10 years ago =

(3x – 10) years.## Solution:

= 3x – 10 = 5 (x – 10)

= 3x – 10 = 5x – 50

= (-10) + 50 = 5x – 3x

= 40 = 2x

Therefore,

x = 20 years.## Conclusion:

Aman’s Son’s present age is

20 years.Aman’s age is 3x = 3 * 20 =

60 years.(An Extract from Class 8 – Mathematics – Linear Equations In One Variable)

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