Area of the triangle whose perimeter is =270 and the ratio of sides are 25:17:12. Question Area of the triangle whose perimeter is =270 and the ratio of sides are 25:17:12. in progress 0 Math Arya 3 weeks 2021-09-06T06:33:57+00:00 2021-09-06T06:33:57+00:00 2 Answers 0 views 0

## Answers ( )

## answer is 2250 m ^2

Step-by-step explanation:hope it helps you

Step-by-step explanation:

area of triangle=√s(s-a) (s-b) (s-c)

here ,s is the semi-perimeter,

and,a,b,c, are the sides of triangle

given perimeter=270cm

semi-perimeter=s=perimeter/2

s=270/2

s=135cm

given ratios of sides is25:17:12

let sides be a=25x , b=17x , c=12x

where x is any no.

now,

perimeter = 270cm

a+b+c = 270cm

25x + 17x + 12x =270cm

42x + 12x =270cm

54x = 270cm

x = 270/54

x=5cm

so , ax=25x = 25*5 = 125cm

bx=17x = 17*5 = 85cm

cx=12x = 12*5 = 60cm

Area of triangle can be calculated by heron/s formula

which comes to 2250m square