Area of the triangle whose perimeter is =270 and the ratio of sides are 25:17:12.

Question

Area of the triangle whose perimeter is =270 and the ratio of sides are 25:17:12.

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Arya 3 weeks 2021-09-06T06:33:57+00:00 2 Answers 0 views 0

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    0
    2021-09-06T06:35:13+00:00

    answer is 2250 m ^2

    Step-by-step explanation:

    hope it helps you

    0
    2021-09-06T06:35:15+00:00

    Step-by-step explanation:

    area of triangle=√s(s-a) (s-b) (s-c)

    here ,s is the semi-perimeter,

    and,a,b,c, are the sides of triangle

    given perimeter=270cm

    semi-perimeter=s=perimeter/2

    s=270/2

    s=135cm

    given ratios of sides is25:17:12

    let sides be a=25x , b=17x , c=12x

    where x is any no.

    now,

    perimeter = 270cm

    a+b+c = 270cm

    25x + 17x + 12x =270cm

    42x + 12x =270cm

    54x = 270cm

    x = 270/54

    x=5cm

    so , ax=25x = 25*5 = 125cm

    bx=17x = 17*5 = 85cm

    cx=12x = 12*5 = 60cm

    Area of triangle can be calculated by heron/s formula

    which comes to 2250m square

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